2x^2+87x+90=0

Solution for 2x^2+87x+90=0 equation:

2x^2+87x+90=0

a = 2; b = 87; c = +90;
Δ = b2-4ac
Δ = 872-4·2·90
Δ = 6849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6849}=\sqrt{9*761}=\sqrt{9}*\sqrt{761}=3\sqrt{761}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(87)-3\sqrt{761}}{2*2}=\frac{-87-3\sqrt{761}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(87)+3\sqrt{761}}{2*2}=\frac{-87+3\sqrt{761}}{4}
$